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Number of solutions to a simple equation
The equation $2^{15}+5^{15}+7^{15}-1^{15}=0$ is a simple equation?
The answer is no! Let a = $2^{15}$, b = $5^{15}$, c = $7^{15}$ and d = $1^{15}$. We have:
$$a+b+c-d=2^{15}+5^{15}+7^{15}-1^{15}=$$
$$2^{15}+5^{15}+7^{15}-2^{15}-5^{15}-7^{15}+1^{15}=$$
$$2^{15}+5^{15}+7^{15}-15^{15}+1^{15}=$$
$$2^{15}+5^{15}+7^{15}+1^{15}(14+15)=$$
$$2^{15}+5^{15}+7^{15}(14+15)$$
$$2^{15}+5^{15}(14+15)+7^{15}=$$
$$\left(2^{15}+5^{15}\right) \left(14+15\right)$$
Hence there are at least seven solution to the equation as $2^{15}+5^{15}$ is a prime number.
Is my proof correct?
A:
Your solution is correct, and more careful.
You wrote $a = 2^{15}$ but if I’m not mistaken there is not such $a$, so we
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